4m+4+2=2(2m+3)

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Solution for 4m+4+2=2(2m+3) equation: 



4m+4+2=2(2m+3)

We move all terms to the left:

4m+4+2-(2(2m+3))=0

We add all the numbers together, and all the variables

4m-(2(2m+3))+6=0



We calculate terms in parentheses: -(2(2m+3)), so:

2(2m+3)

We multiply parentheses

4m+6

Back to the equation:

-(4m+6)



We get rid of parentheses

4m-4m-6+6=0

We add all the numbers together, and all the variables

=0

m=0/1

m=0

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