4m-10=12+2(2m+8)

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Solution for 4m-10=12+2(2m+8) equation: 



4m-10=12+2(2m+8)

We move all terms to the left:

4m-10-(12+2(2m+8))=0



We calculate terms in parentheses: -(12+2(2m+8)), so:

12+2(2m+8)

determiningTheFunctionDomain
2(2m+8)+12

We multiply parentheses

4m+16+12

We add all the numbers together, and all the variables

4m+28

Back to the equation:

-(4m+28)



We get rid of parentheses

4m-4m-28-10=0

We add all the numbers together, and all the variables

-38!=0

There is no solution for this equation

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