4m-2m(m-3)=7m-14

Solution for 4m-2m(m-3)=7m-14 equation:

4m-2m(m-3)=7m-14

We move all terms to the left:

4m-2m(m-3)-(7m-14)=0

We multiply parentheses

-2m^2+4m+6m-(7m-14)=0

We get rid of parentheses

-2m^2+4m+6m-7m+14=0

We add all the numbers together, and all the variables

-2m^2+3m+14=0

a = -2; b = 3; c = +14;
Δ = b2-4ac
Δ = 32-4·(-2)·14
Δ = 121
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$m_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$m_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{121}=11$
$m_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(3)-11}{2*-2}=\frac{-14}{-4}
=3+1/2
$
$m_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(3)+11}{2*-2}=\frac{8}{-4}
=-2
$