4m-3(5+m)=20

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Solution for 4m-3(5+m)=20 equation: 



4m-3(5+m)=20

We move all terms to the left:

4m-3(5+m)-(20)=0

We add all the numbers together, and all the variables

4m-3(m+5)-20=0

We multiply parentheses

4m-3m-15-20=0

We add all the numbers together, and all the variables

m-35=0

We move all terms containing m to the left, all other terms to the right

m=35

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