4m-3=(6m+18)/6

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Solution for 4m-3=(6m+18)/6 equation: 



4m-3=(6m+18)/6

We move all terms to the left:

4m-3-((6m+18)/6)=0

We multiply all the terms by the denominator


4m*6)-((6m+18)-3*6)=0

We add all the numbers together, and all the variables

4m*6)-((6m+18)=0

Wy multiply elements

24m^2=0

a = 24; b = 0; c = 0;
Δ = b2-4ac
Δ = 02-4·24·0
Δ = 0
Delta is equal to zero, so there is only one solution to the equation

                              Stosujemy wzór:
$m=\frac{-b}{2a}=\frac{0}{48}=0$

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