4m-6+2=2(2m-2)

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Solution for 4m-6+2=2(2m-2) equation: 



4m-6+2=2(2m-2)

We move all terms to the left:

4m-6+2-(2(2m-2))=0

We add all the numbers together, and all the variables

4m-(2(2m-2))-4=0



We calculate terms in parentheses: -(2(2m-2)), so:

2(2m-2)

We multiply parentheses

4m-4

Back to the equation:

-(4m-4)



We get rid of parentheses

4m-4m+4-4=0

We add all the numbers together, and all the variables

=0

m=0/1

m=0

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