4m2+28m=-49

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Solution for 4m2+28m=-49 equation: 



4m^2+28m=-49

We move all terms to the left:

4m^2+28m-(-49)=0

We add all the numbers together, and all the variables

4m^2+28m+49=0

a = 4; b = 28; c = +49;
Δ = b2-4ac
Δ = 282-4·4·49
Δ = 0
Delta is equal to zero, so there is only one solution to the equation

                              Stosujemy wzór:
$m=\frac{-b}{2a}=\frac{-28}{8}=-3+1/2$

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