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4m^2+5m+1=0
a = 4; b = 5; c = +1;
Δ = b2-4ac
Δ = 52-4·4·1
Δ = 9
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$m_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$m_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{9}=3$$m_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(5)-3}{2*4}=\frac{-8}{8} =-1 $$m_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(5)+3}{2*4}=\frac{-2}{8} =-1/4 $
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