4m2-27-40=0

Solution for 4m2-27-40=0 equation:

4m^2-27-40=0

We add all the numbers together, and all the variables

4m^2-67=0

a = 4; b = 0; c = -67;
Δ = b2-4ac
Δ = 02-4·4·(-67)
Δ = 1072
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$m_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$m_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{1072}=\sqrt{16*67}=\sqrt{16}*\sqrt{67}=4\sqrt{67}$
$m_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-4\sqrt{67}}{2*4}=\frac{0-4\sqrt{67}}{8}
=-\frac{4\sqrt{67}}{8}
=-\frac{\sqrt{67}}{2}
$
$m_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+4\sqrt{67}}{2*4}=\frac{0+4\sqrt{67}}{8}
=\frac{4\sqrt{67}}{8}
=\frac{\sqrt{67}}{2}
$