4m2=-3m+16

Solution for 4m2=-3m+16 equation:

4m^2=-3m+16

We move all terms to the left:

4m^2-(-3m+16)=0

We get rid of parentheses

4m^2+3m-16=0

a = 4; b = 3; c = -16;
Δ = b2-4ac
Δ = 32-4·4·(-16)
Δ = 265
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$m_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$m_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$m_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(3)-\sqrt{265}}{2*4}=\frac{-3-\sqrt{265}}{8}
$
$m_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(3)+\sqrt{265}}{2*4}=\frac{-3+\sqrt{265}}{8}
$