4n+2(d+3)=12

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Solution for 4n+2(d+3)=12 equation:


Simplifying
4n + 2(d + 3) = 12

Reorder the terms:
4n + 2(3 + d) = 12
4n + (3 * 2 + d * 2) = 12
4n + (6 + 2d) = 12

Reorder the terms:
6 + 2d + 4n = 12

Solving
6 + 2d + 4n = 12

Solving for variable 'd'.

Move all terms containing d to the left, all other terms to the right.

Add '-6' to each side of the equation.
6 + 2d + -6 + 4n = 12 + -6

Reorder the terms:
6 + -6 + 2d + 4n = 12 + -6

Combine like terms: 6 + -6 = 0
0 + 2d + 4n = 12 + -6
2d + 4n = 12 + -6

Combine like terms: 12 + -6 = 6
2d + 4n = 6

Add '-4n' to each side of the equation.
2d + 4n + -4n = 6 + -4n

Combine like terms: 4n + -4n = 0
2d + 0 = 6 + -4n
2d = 6 + -4n

Divide each side by '2'.
d = 3 + -2n

Simplifying
d = 3 + -2n

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