4n+20=(2n+20)+n

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Solution for 4n+20=(2n+20)+n equation:



4n+20=(2n+20)+n
We move all terms to the left:
4n+20-((2n+20)+n)=0
We calculate terms in parentheses: -((2n+20)+n), so:
(2n+20)+n
We add all the numbers together, and all the variables
n+(2n+20)
We get rid of parentheses
n+2n+20
We add all the numbers together, and all the variables
3n+20
Back to the equation:
-(3n+20)
We get rid of parentheses
4n-3n-20+20=0
We add all the numbers together, and all the variables
n=0

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