4n+23=3(n-4)+3

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Solution for 4n+23=3(n-4)+3 equation: 



4n+23=3(n-4)+3

We move all terms to the left:

4n+23-(3(n-4)+3)=0



We calculate terms in parentheses: -(3(n-4)+3), so:

3(n-4)+3

We multiply parentheses

3n-12+3

We add all the numbers together, and all the variables

3n-9

Back to the equation:

-(3n-9)



We get rid of parentheses

4n-3n+9+23=0

We add all the numbers together, and all the variables

n+32=0

We move all terms containing n to the left, all other terms to the right

n=-32

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