4n+3(n+1)=108

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Solution for 4n+3(n+1)=108 equation: 



4n+3(n+1)=108

We move all terms to the left:

4n+3(n+1)-(108)=0

We multiply parentheses

4n+3n+3-108=0

We add all the numbers together, and all the variables

7n-105=0

We move all terms containing n to the left, all other terms to the right

7n=105

n=105/7

n=15

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