4n+3=2(2n+1)+1

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Solution for 4n+3=2(2n+1)+1 equation: 



4n+3=2(2n+1)+1

We move all terms to the left:

4n+3-(2(2n+1)+1)=0



We calculate terms in parentheses: -(2(2n+1)+1), so:

2(2n+1)+1

We multiply parentheses

4n+2+1

We add all the numbers together, and all the variables

4n+3

Back to the equation:

-(4n+3)



We get rid of parentheses

4n-4n-3+3=0

We add all the numbers together, and all the variables

=0

n=0/1

n=0

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