4n+40=8(n-5)+6n

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Solution for 4n+40=8(n-5)+6n equation: 



4n+40=8(n-5)+6n

We move all terms to the left:

4n+40-(8(n-5)+6n)=0



We calculate terms in parentheses: -(8(n-5)+6n), so:

8(n-5)+6n

We add all the numbers together, and all the variables

6n+8(n-5)

We multiply parentheses

6n+8n-40

We add all the numbers together, and all the variables

14n-40

Back to the equation:

-(14n-40)



We get rid of parentheses

4n-14n+40+40=0

We add all the numbers together, and all the variables

-10n+80=0

We move all terms containing n to the left, all other terms to the right

-10n=-80

n=-80/-10

n=+8

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