4n+5+2n=6(n-1)+11

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Solution for 4n+5+2n=6(n-1)+11 equation: 



4n+5+2n=6(n-1)+11

We move all terms to the left:

4n+5+2n-(6(n-1)+11)=0

We add all the numbers together, and all the variables

6n-(6(n-1)+11)+5=0



We calculate terms in parentheses: -(6(n-1)+11), so:

6(n-1)+11

We multiply parentheses

6n-6+11

We add all the numbers together, and all the variables

6n+5

Back to the equation:

-(6n+5)



We get rid of parentheses

6n-6n-5+5=0

We add all the numbers together, and all the variables

=0

n=0/1

n=0

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