4n+6(n-2)=2(n-18)

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Solution for 4n+6(n-2)=2(n-18) equation:



4n+6(n-2)=2(n-18)
We move all terms to the left:
4n+6(n-2)-(2(n-18))=0
We multiply parentheses
4n+6n-(2(n-18))-12=0
We calculate terms in parentheses: -(2(n-18)), so:
2(n-18)
We multiply parentheses
2n-36
Back to the equation:
-(2n-36)
We add all the numbers together, and all the variables
10n-(2n-36)-12=0
We get rid of parentheses
10n-2n+36-12=0
We add all the numbers together, and all the variables
8n+24=0
We move all terms containing n to the left, all other terms to the right
8n=-24
n=-24/8
n=-3

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