4n+8(3n+2)=128

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Solution for 4n+8(3n+2)=128 equation: 



4n+8(3n+2)=128

We move all terms to the left:

4n+8(3n+2)-(128)=0

We multiply parentheses

4n+24n+16-128=0

We add all the numbers together, and all the variables

28n-112=0

We move all terms containing n to the left, all other terms to the right

28n=112

n=112/28

n=4

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