4n-(4n-4)=-6(-n-5)-2

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Solution for 4n-(4n-4)=-6(-n-5)-2 equation: 



4n-(4n-4)=-6(-n-5)-2

We move all terms to the left:

4n-(4n-4)-(-6(-n-5)-2)=0

We add all the numbers together, and all the variables

4n-(4n-4)-(-6(-1n-5)-2)=0

We get rid of parentheses

4n-4n-(-6(-1n-5)-2)+4=0



We calculate terms in parentheses: -(-6(-1n-5)-2), so:

-6(-1n-5)-2

We multiply parentheses

6n+30-2

We add all the numbers together, and all the variables

6n+28

Back to the equation:

-(6n+28)



We add all the numbers together, and all the variables

-(6n+28)+4=0

We get rid of parentheses

-6n-28+4=0

We add all the numbers together, and all the variables

-6n-24=0

We move all terms containing n to the left, all other terms to the right

-6n=24

n=24/-6

n=-4

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