4n-(n+4)=3(1+n)

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Solution for 4n-(n+4)=3(1+n) equation: 



4n-(n+4)=3(1+n)

We move all terms to the left:

4n-(n+4)-(3(1+n))=0

We add all the numbers together, and all the variables

4n-(n+4)-(3(n+1))=0

We get rid of parentheses

4n-n-(3(n+1))-4=0



We calculate terms in parentheses: -(3(n+1)), so:

3(n+1)

We multiply parentheses

3n+3

Back to the equation:

-(3n+3)



We add all the numbers together, and all the variables

3n-(3n+3)-4=0

We get rid of parentheses

3n-3n-3-4=0

We add all the numbers together, and all the variables

-7!=0

There is no solution for this equation

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