4n-(n+8)=2(3n+3)-11

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Solution for 4n-(n+8)=2(3n+3)-11 equation: 



4n-(n+8)=2(3n+3)-11

We move all terms to the left:

4n-(n+8)-(2(3n+3)-11)=0

We get rid of parentheses

4n-n-(2(3n+3)-11)-8=0



We calculate terms in parentheses: -(2(3n+3)-11), so:

2(3n+3)-11

We multiply parentheses

6n+6-11

We add all the numbers together, and all the variables

6n-5

Back to the equation:

-(6n-5)



We add all the numbers together, and all the variables

3n-(6n-5)-8=0

We get rid of parentheses

3n-6n+5-8=0

We add all the numbers together, and all the variables

-3n-3=0

We move all terms containing n to the left, all other terms to the right

-3n=3

n=3/-3

n=-1

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