4n-38=4(6n+1)+n

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Solution for 4n-38=4(6n+1)+n equation: 



4n-38=4(6n+1)+n

We move all terms to the left:

4n-38-(4(6n+1)+n)=0



We calculate terms in parentheses: -(4(6n+1)+n), so:

4(6n+1)+n

We add all the numbers together, and all the variables

n+4(6n+1)

We multiply parentheses

n+24n+4

We add all the numbers together, and all the variables

25n+4

Back to the equation:

-(25n+4)



We get rid of parentheses

4n-25n-4-38=0

We add all the numbers together, and all the variables

-21n-42=0

We move all terms containing n to the left, all other terms to the right

-21n=42

n=42/-21

n=-2

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