4n-4=6(n+2)+4

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Solution for 4n-4=6(n+2)+4 equation: 



4n-4=6(n+2)+4

We move all terms to the left:

4n-4-(6(n+2)+4)=0



We calculate terms in parentheses: -(6(n+2)+4), so:

6(n+2)+4

We multiply parentheses

6n+12+4

We add all the numbers together, and all the variables

6n+16

Back to the equation:

-(6n+16)



We get rid of parentheses

4n-6n-16-4=0

We add all the numbers together, and all the variables

-2n-20=0

We move all terms containing n to the left, all other terms to the right

-2n=20

n=20/-2

n=-10

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