4n-5(3n-29)=24

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Solution for 4n-5(3n-29)=24 equation: 



4n-5(3n-29)=24

We move all terms to the left:

4n-5(3n-29)-(24)=0

We multiply parentheses

4n-15n+145-24=0

We add all the numbers together, and all the variables

-11n+121=0

We move all terms containing n to the left, all other terms to the right

-11n=-121

n=-121/-11

n=+11

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