4n2+24n+25=4n

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Solution for 4n2+24n+25=4n equation: 



4n^2+24n+25=4n

We move all terms to the left:

4n^2+24n+25-(4n)=0

We add all the numbers together, and all the variables

4n^2+20n+25=0

a = 4; b = 20; c = +25;
Δ = b2-4ac
Δ = 202-4·4·25
Δ = 0
Delta is equal to zero, so there is only one solution to the equation

                              Stosujemy wzór:
$n=\frac{-b}{2a}=\frac{-20}{8}=-2+1/2$

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