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4n^2+36n+72=0
a = 4; b = 36; c = +72;
Δ = b2-4ac
Δ = 362-4·4·72
Δ = 144
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$n_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$n_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{144}=12$$n_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(36)-12}{2*4}=\frac{-48}{8} =-6 $$n_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(36)+12}{2*4}=\frac{-24}{8} =-3 $
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