4n2+5n-250=0

Solution for 4n2+5n-250=0 equation:

4n^2+5n-250=0

a = 4; b = 5; c = -250;
Δ = b2-4ac
Δ = 52-4·4·(-250)
Δ = 4025
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$n_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$n_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{4025}=\sqrt{25*161}=\sqrt{25}*\sqrt{161}=5\sqrt{161}$
$n_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(5)-5\sqrt{161}}{2*4}=\frac{-5-5\sqrt{161}}{8}
$
$n_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(5)+5\sqrt{161}}{2*4}=\frac{-5+5\sqrt{161}}{8}
$