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4n^2-25n+25=0
a = 4; b = -25; c = +25;
Δ = b2-4ac
Δ = -252-4·4·25
Δ = 225
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$n_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$n_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{225}=15$$n_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-25)-15}{2*4}=\frac{10}{8} =1+1/4 $$n_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-25)+15}{2*4}=\frac{40}{8} =5 $
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