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4n^2=304
We move all terms to the left:
4n^2-(304)=0
a = 4; b = 0; c = -304;
Δ = b2-4ac
Δ = 02-4·4·(-304)
Δ = 4864
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$n_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$n_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{4864}=\sqrt{256*19}=\sqrt{256}*\sqrt{19}=16\sqrt{19}$$n_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-16\sqrt{19}}{2*4}=\frac{0-16\sqrt{19}}{8} =-\frac{16\sqrt{19}}{8} =-2\sqrt{19} $$n_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+16\sqrt{19}}{2*4}=\frac{0+16\sqrt{19}}{8} =\frac{16\sqrt{19}}{8} =2\sqrt{19} $
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