4p+4/2p-3=10

Solution for 4p+4/2p-3=10 equation:

4p+4/2p-3=10

We move all terms to the left:

4p+4/2p-3-(10)=0


Domain of the equation: 2p!=0

p!=0/2

p!=0

p∈R


We add all the numbers together, and all the variables

4p+4/2p-13=0

We multiply all the terms by the denominator


4p*2p-13*2p+4=0

Wy multiply elements

8p^2-26p+4=0

a = 8; b = -26; c = +4;
Δ = b2-4ac
Δ = -262-4·8·4
Δ = 548
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$p_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$p_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{548}=\sqrt{4*137}=\sqrt{4}*\sqrt{137}=2\sqrt{137}$
$p_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-26)-2\sqrt{137}}{2*8}=\frac{26-2\sqrt{137}}{16}
$
$p_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-26)+2\sqrt{137}}{2*8}=\frac{26+2\sqrt{137}}{16}
$