4p+4/2p-6=10

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Solution for 4p+4/2p-6=10 equation:



4p+4/2p-6=10
We move all terms to the left:
4p+4/2p-6-(10)=0
Domain of the equation: 2p!=0
p!=0/2
p!=0
p∈R
We add all the numbers together, and all the variables
4p+4/2p-16=0
We multiply all the terms by the denominator
4p*2p-16*2p+4=0
Wy multiply elements
8p^2-32p+4=0
a = 8; b = -32; c = +4;
Δ = b2-4ac
Δ = -322-4·8·4
Δ = 896
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$p_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$p_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:
$\sqrt{\Delta}=\sqrt{896}=\sqrt{64*14}=\sqrt{64}*\sqrt{14}=8\sqrt{14}$
$p_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-32)-8\sqrt{14}}{2*8}=\frac{32-8\sqrt{14}}{16} $
$p_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-32)+8\sqrt{14}}{2*8}=\frac{32+8\sqrt{14}}{16} $

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