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4p/3p=p
We move all terms to the left:
4p/3p-(p)=0
Domain of the equation: 3p!=0We add all the numbers together, and all the variables
p!=0/3
p!=0
p∈R
-1p+4p/3p=0
We multiply all the terms by the denominator
-1p*3p+4p=0
We add all the numbers together, and all the variables
4p-1p*3p=0
Wy multiply elements
-3p^2+4p=0
a = -3; b = 4; c = 0;
Δ = b2-4ac
Δ = 42-4·(-3)·0
Δ = 16
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$p_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$p_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{16}=4$$p_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(4)-4}{2*-3}=\frac{-8}{-6} =1+1/3 $$p_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(4)+4}{2*-3}=\frac{0}{-6} =0 $
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