4p2=448

Solution for 4p2=448 equation:

4p^2=448

We move all terms to the left:

4p^2-(448)=0

a = 4; b = 0; c = -448;
Δ = b2-4ac
Δ = 02-4·4·(-448)
Δ = 7168
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$p_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$p_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{7168}=\sqrt{1024*7}=\sqrt{1024}*\sqrt{7}=32\sqrt{7}$
$p_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-32\sqrt{7}}{2*4}=\frac{0-32\sqrt{7}}{8}
=-\frac{32\sqrt{7}}{8}
=-4\sqrt{7}
$
$p_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+32\sqrt{7}}{2*4}=\frac{0+32\sqrt{7}}{8}
=\frac{32\sqrt{7}}{8}
=4\sqrt{7}
$