4q-32=5(3-2q)

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Solution for 4q-32=5(3-2q) equation: 



4q-32=5(3-2q)

We move all terms to the left:

4q-32-(5(3-2q))=0

We add all the numbers together, and all the variables

4q-(5(-2q+3))-32=0



We calculate terms in parentheses: -(5(-2q+3)), so:

5(-2q+3)

We multiply parentheses

-10q+15

Back to the equation:

-(-10q+15)



We get rid of parentheses

4q+10q-15-32=0

We add all the numbers together, and all the variables

14q-47=0

We move all terms containing q to the left, all other terms to the right

14q=47

q=47/14

q=3+5/14

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