4q-5=2+3(q-3)

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Solution for 4q-5=2+3(q-3) equation:



4q-5=2+3(q-3)
We move all terms to the left:
4q-5-(2+3(q-3))=0
We calculate terms in parentheses: -(2+3(q-3)), so:
2+3(q-3)
determiningTheFunctionDomain 3(q-3)+2
We multiply parentheses
3q-9+2
We add all the numbers together, and all the variables
3q-7
Back to the equation:
-(3q-7)
We get rid of parentheses
4q-3q+7-5=0
We add all the numbers together, and all the variables
q+2=0
We move all terms containing q to the left, all other terms to the right
q=-2

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