4r(2r+1)+2r+5=0

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Solution for 4r(2r+1)+2r+5=0 equation: 



4r(2r+1)+2r+5=0

We add all the numbers together, and all the variables

2r+4r(2r+1)+5=0

We multiply parentheses

8r^2+2r+4r+5=0

We add all the numbers together, and all the variables

8r^2+6r+5=0

a = 8; b = 6; c = +5;
Δ = b2-4ac
Δ = 62-4·8·5
Δ = -124
Delta is less than zero, so there is no solution for the equation

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