4r(r-1)+1=0

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Solution for 4r(r-1)+1=0 equation: 



4r(r-1)+1=0

We multiply parentheses

4r^2-4r+1=0

a = 4; b = -4; c = +1;
Δ = b2-4ac
Δ = -42-4·4·1
Δ = 0
Delta is equal to zero, so there is only one solution to the equation

                              Stosujemy wzór:
$r=\frac{-b}{2a}=\frac{4}{8}=1/2$

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