4r+12=2(2r+3)+6

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Solution for 4r+12=2(2r+3)+6 equation: 



4r+12=2(2r+3)+6

We move all terms to the left:

4r+12-(2(2r+3)+6)=0



We calculate terms in parentheses: -(2(2r+3)+6), so:

2(2r+3)+6

We multiply parentheses

4r+6+6

We add all the numbers together, and all the variables

4r+12

Back to the equation:

-(4r+12)



We get rid of parentheses

4r-4r-12+12=0

We add all the numbers together, and all the variables

=0

r=0/1

r=0

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