4r+2(3r-5)+6r-12=74

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Solution for 4r+2(3r-5)+6r-12=74 equation: 



4r+2(3r-5)+6r-12=74

We move all terms to the left:

4r+2(3r-5)+6r-12-(74)=0

We add all the numbers together, and all the variables

10r+2(3r-5)-86=0

We multiply parentheses

10r+6r-10-86=0

We add all the numbers together, and all the variables

16r-96=0

We move all terms containing r to the left, all other terms to the right

16r=96

r=96/16

r=6

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