4r+6(2+3)=12r-6

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Solution for 4r+6(2+3)=12r-6 equation:



4r+6(2+3)=12r-6
We move all terms to the left:
4r+6(2+3)-(12r-6)=0
We add all the numbers together, and all the variables
4r-(12r-6)+65=0
We get rid of parentheses
4r-12r+6+65=0
We add all the numbers together, and all the variables
-8r+71=0
We move all terms containing r to the left, all other terms to the right
-8r=-71
r=-71/-8
r=8+7/8

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