4r-1=5+5(-4-2r)

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Solution for 4r-1=5+5(-4-2r) equation: 



4r-1=5+5(-4-2r)

We move all terms to the left:

4r-1-(5+5(-4-2r))=0

We add all the numbers together, and all the variables

4r-(5+5(-2r-4))-1=0



We calculate terms in parentheses: -(5+5(-2r-4)), so:

5+5(-2r-4)

determiningTheFunctionDomain
5(-2r-4)+5

We multiply parentheses

-10r-20+5

We add all the numbers together, and all the variables

-10r-15

Back to the equation:

-(-10r-15)



We get rid of parentheses

4r+10r+15-1=0

We add all the numbers together, and all the variables

14r+14=0

We move all terms containing r to the left, all other terms to the right

14r=-14

r=-14/14

r=-1

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