4r-3=3(r+4)

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Solution for 4r-3=3(r+4) equation: 



4r-3=3(r+4)

We move all terms to the left:

4r-3-(3(r+4))=0



We calculate terms in parentheses: -(3(r+4)), so:

3(r+4)

We multiply parentheses

3r+12

Back to the equation:

-(3r+12)



We get rid of parentheses

4r-3r-12-3=0

We add all the numbers together, and all the variables

r-15=0

We move all terms containing r to the left, all other terms to the right

r=15

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