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4r-5=2-(5-5r)
We move all terms to the left:
4r-5-(2-(5-5r))=0
We add all the numbers together, and all the variables
4r-(2-(-5r+5))-5=0
We calculate terms in parentheses: -(2-(-5r+5)), so:We get rid of parentheses
2-(-5r+5)
determiningTheFunctionDomain -(-5r+5)+2
We get rid of parentheses
5r-5+2
We add all the numbers together, and all the variables
5r-3
Back to the equation:
-(5r-3)
4r-5r+3-5=0
We add all the numbers together, and all the variables
-1r-2=0
We move all terms containing r to the left, all other terms to the right
-r=2
r=2/-1
r=-2
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