4r-7(2r+8)=4(1+7r)

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Solution for 4r-7(2r+8)=4(1+7r) equation: 



4r-7(2r+8)=4(1+7r)

We move all terms to the left:

4r-7(2r+8)-(4(1+7r))=0

We add all the numbers together, and all the variables

4r-7(2r+8)-(4(7r+1))=0

We multiply parentheses

4r-14r-(4(7r+1))-56=0



We calculate terms in parentheses: -(4(7r+1)), so:

4(7r+1)

We multiply parentheses

28r+4

Back to the equation:

-(28r+4)



We add all the numbers together, and all the variables

-10r-(28r+4)-56=0

We get rid of parentheses

-10r-28r-4-56=0

We add all the numbers together, and all the variables

-38r-60=0

We move all terms containing r to the left, all other terms to the right

-38r=60

r=60/-38

r=-1+11/19

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