4r/2+3(2r-6)=93

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Solution for 4r/2+3(2r-6)=93 equation: 



4r/2+3(2r-6)=93

We move all terms to the left:

4r/2+3(2r-6)-(93)=0

We multiply parentheses

4r/2+6r-18-93=0

We multiply all the terms by the denominator


4r+6r*2-18*2-93*2=0

We add all the numbers together, and all the variables

4r+6r*2-222=0

Wy multiply elements

4r+12r-222=0

We add all the numbers together, and all the variables

16r-222=0

We move all terms containing r to the left, all other terms to the right

16r=222

r=222/16

r=13+7/8

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