4r/2+3(2r-6)=96

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Solution for 4r/2+3(2r-6)=96 equation:



4r/2+3(2r-6)=96
We move all terms to the left:
4r/2+3(2r-6)-(96)=0
We multiply parentheses
4r/2+6r-18-96=0
We multiply all the terms by the denominator
4r+6r*2-18*2-96*2=0
We add all the numbers together, and all the variables
4r+6r*2-228=0
Wy multiply elements
4r+12r-228=0
We add all the numbers together, and all the variables
16r-228=0
We move all terms containing r to the left, all other terms to the right
16r=228
r=228/16
r=14+1/4

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