4s+(3-s)=6-(s-3)

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Solution for 4s+(3-s)=6-(s-3) equation: 



4s+(3-s)=6-(s-3)

We move all terms to the left:

4s+(3-s)-(6-(s-3))=0

We add all the numbers together, and all the variables

4s+(-1s+3)-(6-(s-3))=0

We get rid of parentheses

4s-1s-(6-(s-3))+3=0



We calculate terms in parentheses: -(6-(s-3)), so:

6-(s-3)

determiningTheFunctionDomain
-(s-3)+6

We get rid of parentheses

-s+3+6

We add all the numbers together, and all the variables

-1s+9

Back to the equation:

-(-1s+9)



We add all the numbers together, and all the variables

3s-(-1s+9)+3=0

We get rid of parentheses

3s+1s-9+3=0

We add all the numbers together, and all the variables

4s-6=0

We move all terms containing s to the left, all other terms to the right

4s=6

s=6/4

s=1+1/2

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