4s-5+2(s+3)s=148

Solution for 4s-5+2(s+3)s=148 equation:

4s-5+2(s+3)s=148

We move all terms to the left:

4s-5+2(s+3)s-(148)=0

We add all the numbers together, and all the variables

4s+2(s+3)s-153=0

We multiply parentheses

2s^2+4s+6s-153=0

We add all the numbers together, and all the variables

2s^2+10s-153=0

a = 2; b = 10; c = -153;
Δ = b2-4ac
Δ = 102-4·2·(-153)
Δ = 1324
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$s_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$s_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{1324}=\sqrt{4*331}=\sqrt{4}*\sqrt{331}=2\sqrt{331}$
$s_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(10)-2\sqrt{331}}{2*2}=\frac{-10-2\sqrt{331}}{4}
$
$s_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(10)+2\sqrt{331}}{2*2}=\frac{-10+2\sqrt{331}}{4}
$