4s-7=2+3(s+5)

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Solution for 4s-7=2+3(s+5) equation: 



4s-7=2+3(s+5)

We move all terms to the left:

4s-7-(2+3(s+5))=0



We calculate terms in parentheses: -(2+3(s+5)), so:

2+3(s+5)

determiningTheFunctionDomain
3(s+5)+2

We multiply parentheses

3s+15+2

We add all the numbers together, and all the variables

3s+17

Back to the equation:

-(3s+17)



We get rid of parentheses

4s-3s-17-7=0

We add all the numbers together, and all the variables

s-24=0

We move all terms containing s to the left, all other terms to the right

s=24

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